Ex 6.1, 18 (MCQ) - Chapter 6 Class 12 Application of Derivatives
Last updated at August 13, 2026 by Teachoo
Finding rate of change
Example 1
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Chapter 6 Class 12 Application of Derivatives
Concept wise
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Finding rate of change
- To show increasing/decreasing in whole domain
- To show increasing/decreasing in intervals
- Find intervals of increasing/decreasing
- Finding slope of tangent/normal
- Finding point when tangent is parallel/ perpendicular
- Finding equation of tangent/normal when point and curve is given
- Finding equation of tangent/normal when slope and curve are given
- Finding approximate value of numbers
- Finding approximate value of function
- Finding approximate value- Statement questions
- Finding minimum and maximum values from graph
- Local maxima and minima
- Minima/ maxima (statement questions) - Number questions
- Minima/ maxima (statement questions) - Geometry questions
- Absolute minima/maxima
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Transcript
Ex 6.1, 18 The total revenue in Rupees received from the sale of š„ units of a product is given by R(š„) = 3š„2 + 36š„ + 5. The marginal revenue, when š„ = 15 is (A) 116 (B) 96 (C) 90 (D) 126Marginal revenue is rate of change of total revenue w. r. t the number of unit sold Let MR be marginal revenue So, MR = š š¹/š š Given, Total revenue = R (š„) = 3š„2 + 36š„ + 5 We need to find marginal revenue when š„ = 15 i.e. MR when š„ = 15 MR = š(š (š„))/šš„ MR = (š (3š„2 + 36š„ + 5) )/šš„ MR = (š(3š„2))/šš„ + (š(36š„))/šš„ + (š(5))/šš„ MR = 3 (š(š„2))/šš„ + 36 (š(š„))/šš„ + 0 MR = 3 Ć 2š„ + 36 MR = 6š + 36 MR when š = 15 MR = 6(15) + 36 MR = 90 + 36 MR = 126 Hence, the required marginal revenue is Rs. 126 Thus, D is the correct Answer
