

Finding rate of change
Ex 6.1, 1 Deleted for CBSE Board 2022 Exams
Ex 6.1,17 (MCQ) Deleted for CBSE Board 2022 Exams
Example 5 Deleted for CBSE Board 2022 Exams
Ex 6.1,15 Important Deleted for CBSE Board 2022 Exams
Example 6 Deleted for CBSE Board 2022 Exams
Ex 6.1,16 Deleted for CBSE Board 2022 Exams
Ex 6.1, 18 (MCQ) Important Deleted for CBSE Board 2022 Exams
Example 2 Deleted for CBSE Board 2022 Exams
Ex 6.1,2 Deleted for CBSE Board 2022 Exams
Example 49 Deleted for CBSE Board 2022 Exams
Example 3 Deleted for CBSE Board 2022 Exams
Ex 6.1,5 Important Deleted for CBSE Board 2022 Exams
Ex 6.1,3 Deleted for CBSE Board 2022 Exams
Ex 6.1,6 Deleted for CBSE Board 2022 Exams
Ex 6.1,12 Deleted for CBSE Board 2022 Exams
Ex 6.1,13 Important Deleted for CBSE Board 2022 Exams
Misc. 19 (MCQ) Deleted for CBSE Board 2022 Exams
Ex 6.1,14 Deleted for CBSE Board 2022 Exams
Example 43 Important Deleted for CBSE Board 2022 Exams
Ex 6.1,4 Important Deleted for CBSE Board 2022 Exams
Example 42 Important Deleted for CBSE Board 2022 Exams
Example 4 Important Deleted for CBSE Board 2022 Exams
Ex 6.1,7 Deleted for CBSE Board 2022 Exams
Ex 6.1,8 Deleted for CBSE Board 2022 Exams
Ex 6.1,9 Deleted for CBSE Board 2022 Exams You are here
Ex 6.1,11 Important Deleted for CBSE Board 2022 Exams
Misc 3 Important
Ex 6.1,10 Important Deleted for CBSE Board 2022 Exams
Example 44 Important Deleted for CBSE Board 2022 Exams
Finding rate of change
Last updated at April 19, 2021 by Teachoo
Ex 6.1, 9 A balloon, which always remains spherical has a variable radius. Find the rate at which its volume is increasing with the radius when the later is 10 cm.Since Balloon is spherical Let r be the radius of balloon . & V be the volume of balloon. We need to find rate at which balloon volume is increasing when radius is 10cm i.e. We need to find change of volume w.r.t radius when r = 10 i.e. we need to find π π½/π π when r = 10 cm We know that Volume of sphere = V = 4/3 Οr3 Now, ππ/ππ = (π (4/3 ππ3))/ππ ππ/ππ = 4/3 Ο π(π3)/ππ ππ/ππ = 4/3 Ο 3π^2 ππ/ππ = 4ππ^2 When r = 10 ππ/ππ = 4 Γ Ο Γ (10)2 ππ/ππ = 400Ο Since volume is in cm3 & Radius is in cm So, ππ/ππ = 400Ο cm3/cm Hence, volume is increasing at the rate of 400 Ο cm3/cm when r = 10 cm