Last updated at Feb. 1, 2020 by Teachoo
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Example 19 Find the equation of the plane with intercepts 2, 3 and 4 on the x, y and z-axis respectively. The equation of a plane with intercepts ๐, b, c on x, y, and z โ axis respectively is ๐/๐ + ๐/๐ + ๐/๐ = 1 Given, Intercept on x โ axis = 2 โด ๐ = 2 Intercept on y โ axis = 3 โด b = 3 Intercept on z โ axis = 4 โด c = 4 Equation of plane is ๐/๐ + ๐/๐ + ๐/๐ = 1 6๐ฅ/12 + 4๐ฆ/12 + 3๐ง/12 = 1 (6๐ฅ + 4๐ฆ + 3๐ง)/12 = 1 6x + 4y + 3z = 12
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