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Example 19 - Find equation of plane with intercepts 2, 3, 4

Example 19 - Chapter 11 Class 12 Three Dimensional Geometry - Part 2

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Example 19 Find the equation of the plane with intercepts 2, 3 and 4 on the x, y and z-axis respectively. The equation of a plane with intercepts π‘Ž, b, c on x, y, and z – axis respectively is 𝒙/𝒂 + π’š/𝒃 + 𝒛/𝒄 = 1 Given, Intercept on x βˆ’ axis = 2 ∴ π‘Ž = 2 Intercept on y βˆ’ axis = 3 ∴ b = 3 Intercept on z – axis = 4 ∴ c = 4 Equation of plane is 𝒙/𝟐 + π’š/πŸ‘ + 𝒛/πŸ’ = 1 6π‘₯/12 + 4𝑦/12 + 3𝑧/12 = 1 (6π‘₯ + 4𝑦 + 3𝑧)/12 = 1 6x + 4y + 3z = 12

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