Last updated at May 29, 2018 by Teachoo

Transcript

Misc 20 (Method 1) Find the vector equation of the line passing through the point (1, 2, 4) and perpendicular to the two lines: 8 3 = + 19 16 = 10 7 and 15 3 = 29 8 = 5 5 The vector equation of a line passing through a point with position vector and parallel to a vector is = + The line passes through (1,2, 4) So, = 1 + 2 4 Given, line is perpendicular to both lines is perpendicular to both lines We know that is perpendicular to both & So, is cross product of both lines 8 3 = + 19 16 = 10 7 and 15 3 = 29 8 = 5 5 Required normal = 3 16 7 3 8 5 = ( 16(-5) 8(7)) (3(-5) 3(7)) + (3(8) 3( 16)) = (80 56) ( 15 21) + (24 + 48) = 24 + 36 + 72 Thus, = 24 + 36 + 72 Now, Putting value of & in formula = + = (1 + 2 4 ) + (24 + 36 + 72 ) = ( + 2 4 ) + 12 (2 + 3 + 6 ) = ( + 2 4 ) + (2 + 3 + 6 ) Therefore, the equation of the line is ( + 2 4 ) + (2 + 3 + 6 ). Misc 20 (Method 2) Find the vector equation of the line passing through the point (1, 2, 4) and perpendicular to the two lines: 8 3 = + 19 16 = 10 7 and 15 3 = 29 8 = 5 5 The vector equation of a line passing through a point with position vector and parallel to a vector is = + The line passes through (1,2, 4) So, = 1 + 2 4 Let = x + y + z Two lines with direction ratios 1 , 1 , 1 and 2 , 2 , 2 are perpendicular if + + = 0 Given, line is perpendicular to 8 3 = + 19 16 = 10 7 and 15 3 = 29 8 = 5 5 So, 3x 16y + 7z = 0 and 3x + 8y 5z = 0 80 56 = 21 ( 15) = 24 ( 48) 24 = 36 = 72 2 = 3 = 6 = k Hence, x = 2k , y = 3k , & z = 6k Thus, = x + y + z = 2k + 3k + 6k Now, Putting value of & in formula = + = ( + 2 4 ) + (2k + 3k + 6k ) = ( + 2 4 ) + k (2 + 3 + 6 ) = ( + 2 4 ) + (2 + 3 + 6 ) Therefore, the equation of the line is ( + 2 4 ) + (2 + 3 + 6 )

Miscellaneous

Misc 1
Important

Misc 2

Misc 3

Misc 4 Important

Misc 5 Important

Misc 6 Important

Misc 7

Misc 8 Important

Misc 9 Important

Misc 10

Misc 11 Important

Misc 12 Important

Misc 13 Important

Misc 14 Important

Misc 15 Important

Misc 16 Important

Misc 17 Important

Misc 18 Important

Misc 19 Important

Misc 20 Important You are here

Misc 21 Important

Misc 22 Important

Misc 23 Important

Chapter 11 Class 12 Three Dimensional Geometry

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.