Misc 6 - Chapter 11 Class 12 Three Dimensional Geometry
Last updated at Sept. 21, 2018 by Teachoo
Transcript
Misc 6 If the lines 1 3 = 2 2 = 3 2 and 1 3 = 1 1 = 6 5 are perpendicular, find the value of k. Two lines 1 1 = 1 1 = 1 1 and 2 2 = 2 2 = 2 2 are perpendicular to each other if + + = 0 Given, Since the two lines are perpendicular, 1 2 + 1 2 + c1 2 = 0 ( 3 3k) + (2k 1) + (2 5) = 0 9k + 2k 10 = 0 7k = 10 k = Therefore, k = 10 7
Chapter 11 Class 12 Three Dimensional Geometry
Serial order wise
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