Misc 16 (MCQ) - Chapter 8 Class 12 Application of Integrals (Term 2)
Last updated at Aug. 11, 2021 by Teachoo
Miscellaneous
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Misc 3
Misc 4 Important
Misc 5 Important
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Misc 11 Important
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Misc 13
Misc 14 Important
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Miscellaneous
Last updated at Aug. 11, 2021 by Teachoo
Misc 16 Area bounded by the curve π¦=π₯3, the π₯-axis and the ordinates π₯ = β 2 and π₯ = 1 is (A) β 9 (B) (β15)/4 (C) 15/4 (D) 17/4 Area Required = Area ABO + Area DCO Area ABO Area ABO =β«_(β2)^0βγπ¦ ππ₯γ Here, π¦=π₯^3 Therefore, Area ABO =β«_(β2)^0βγπ₯^3 ππ₯γ γ=[π₯^4/4]γ_(β2)^0 =1/4 [0β(β2)^4 ] =1/4 Γ (β16) =β4 Since Area is always positive, Area ABO = 4 Area DCO Area DCO = β«_0^1βγπ¦ ππ₯γ =β«_0^1βγπ₯^3 ππ₯γ =[π₯^4/4]_0^1 =1/4 [1^3β0^3 ] =1/4 β΄ Area Required = Area ABO + Area DCO =4+1/4 =17/4 β΄ D is the Correct Option