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Last updated at Dec. 12, 2019 by Teachoo
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Misc 16 Area bounded by the curve ๐ฆ=๐ฅ3, the ๐ฅ-axis and the ordinates ๐ฅ = โ 2 and ๐ฅ = 1 is (A) โ 9 (B) (โ15)/4 (C) 15/4 (D) 17/4 Area Required = Area ABO + Area DCO Area ABO Area ABO =โซ_(โ2)^0โใ๐ฆ ๐๐ฅใ Here, ๐ฆ=๐ฅ^3 Therefore, Area ABO =โซ_(โ2)^0โใ๐ฅ^3 ๐๐ฅใ ใ=[๐ฅ^4/4]ใ_(โ2)^0 =1/4 [0โ(โ2)^4 ] =1/4 ร (โ16) =โ4 Since Area is always positive, Area ABO = 4 Area DCO Area DCO = โซ_0^1โใ๐ฆ ๐๐ฅใ =โซ_0^1โใ๐ฅ^3 ๐๐ฅใ =[๐ฅ^4/4]_0^1 =1/4 [1^3โ0^3 ] =1/4 โด Area Required = Area ABO + Area DCO =4+1/4 =17/4 โด D is the Correct Option
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