Miscellaneous
Miscellaneous
Last updated at August 2, 2026 by Teachoo
Transcript
Misc 1 Find the area under the given curves and given lines: (ii) š¦= š„4, š„ = 1, š„ = 5 and š„-axisArea required = Area ABCD = ā«_1^5ā暦 šš„ć y ā Equation of curve š¦=š„^2 Thus, Area required = ā«_1^5ā暦 šš„ć =ā«_š^šāćš^š š šć =[š„^5/5]_1^5 =5^5/5ā1^5/5 =5^4ā1/5 = 625 ā 0.2 = 624.8 square units