Question 4 - Miscellaneous - Chapter 8 Class 12 Application of Integrals

Last updated at August 18, 2026 by

Misc 7 - Find area enclosed by 4y = 3x2 and line 2y = 3x + 12 - Area between curve and line

Misc 7 - Chapter 8 Class 12 Application of Integrals - Part 2
Misc 7 - Chapter 8 Class 12 Application of Integrals - Part 3 Misc 7 - Chapter 8 Class 12 Application of Integrals - Part 4 Misc 7 - Chapter 8 Class 12 Application of Integrals - Part 5 Misc 7 - Chapter 8 Class 12 Application of Integrals - Part 6

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Transcript

Question 4 Find the area enclosed by the parabola 4𝑦=3𝑥2 and the line 2𝑦 = 3𝑥 + 12 Area ADOEB = ∫1_(−2)^4▒〖(3/2 𝑥+6) 𝑑𝑥〗 = [3/2 (𝑥^2/2)+6𝑥]_(−2)^4 = [(3𝑥^2)/4+6𝑥]_(−2)^4 = [(3(4^2))/4+6(4)] – [(3〖(−2)〗^2)/4+6(−2)] = [12+24] – [3−12] = 36 + 9 = 45 Area required = Area ADOEB – Area ADOEBC = 45 – 18 = 27

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