Misc 3 - Find area bounded by y = sin x between x = 0, 2pi - Miscellaneous

part 2 - Misc 3 - Miscellaneous - Serial order wise - Chapter 8 Class 12 Application of Integrals
part 3 - Misc 3 - Miscellaneous - Serial order wise - Chapter 8 Class 12 Application of Integrals

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Misc 3 Find the area bounded by the curve 𝑦=sin⁑π‘₯ between π‘₯=0 and π‘₯=2πœ‹ Area Required = Area OAB + Area BCD Area OAB = ∫_0^πœ‹β–’γ€–π‘¦ 𝑑π‘₯γ€— 𝑦→sin⁑π‘₯ = ∫_𝟎^𝝅▒〖𝐬𝐒𝐧⁑𝒙 𝒅𝒙〗 = [βˆ’cos⁑π‘₯ ]_β–ˆ( @0)^πœ‹ =βˆ’ [cosβ‘πœ‹βˆ’cos⁑0 ] =βˆ’[βˆ’1βˆ’1] =βˆ’[βˆ’2] = 2 Area BCD = ∫_πœ‹^2πœ‹β–’γ€–π‘¦ 𝑑π‘₯γ€— = ∫_𝝅^πŸπ…β–’γ€–π’”π’Šπ’β‘π’™ 𝒅𝒙〗 = [βˆ’cos⁑π‘₯ ]_β–ˆ( @ @πœ‹)^2πœ‹ =βˆ’ [cos⁑2πœ‹βˆ’cosβ‘πœ‹ ] =βˆ’[1βˆ’(βˆ’1)] = – 2 Since area cannot be negative, Area BCD = 2 Hence, Area Required = Area OAB + Area BCD = 2+2 = πŸ’ square units

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