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Misc 3 - Find area bounded by y = 4x2, x = 0, y = 1, y = 4 - Miscellaneous

Misc 3 - Chapter 8 Class 12 Application of Integrals - Part 2
Misc 3 - Chapter 8 Class 12 Application of Integrals - Part 3


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Misc 3 Find the area of the region lying in the first quadrant and bounded by =4 2 , = 0, =1 and =4 Area required = Area ABCD = 1 4 y equation of parabola = 4 2 4x2 = y x2 = 4 x = 4 x = 2 Thus, Area required = 1 4 = 1 2 4 2 =4 3 3 1 2 = 1 3 2 3 1 3 = 1 3 8 1 = 7 3 Thus, Area required = 1 4 = 1 4 2 = 1 2 1 4 1 2 = 1 2 1 2 +1 1 2 +1 1 4 = 1 2 3 2 3 2 1 4 = 1 2 2 3 3 2 1 4 = 1 3 4 3 2 1 3 2 = 2 3 = 1 3 2 2 3 2 1 = 1 3 2 3 1 =

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.