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Miscellaneous
Misc 1 (ii) Important
Misc 2 Deleted for CBSE Board 2023 Exams
Misc 3
Misc 4 Important You are here
Misc 5 Important
Misc 6 Important
Misc 7
Misc 8
Misc 9 Important
Misc 10
Misc 11 Important
Misc 12 Important Deleted for CBSE Board 2023 Exams
Misc 13
Misc 14 Important
Misc 15 Deleted for CBSE Board 2023 Exams
Misc 16 (MCQ)
Misc 17 (MCQ) Important
Misc 18 (MCQ) Deleted for CBSE Board 2023 Exams
Misc 19 (MCQ) Important Deleted for CBSE Board 2023 Exams
Miscellaneous
Last updated at Dec. 12, 2019 by Teachoo
Misc 4 Sketch the graph of y = |π₯+3| and evaluate β«_(β6)^0βγβπ₯+3β ππ₯γ Letβs Draw the graph y = |π+π| y = |π₯+3| = {β(π₯+3 πππ π₯+3β₯0@β(π₯+3) πππ π₯+3<0 )β€ = {β(π₯+3 πππ π₯β₯β3@β(π₯+3) πππ π₯+3<β3 )β€ Now, Required Area = β«_(βπ)^πβγβπ+πβ π πγ =β«_(β6)^(β3)βγβπ₯+3β ππ₯γ ββ«_(β3)^0βγβπ₯+3β ππ₯γ =β«_(β6)^(β3)βγβ(π₯+3) ππ₯ +β«_(β3)^0βγ(π₯+3) ππ₯γγ =[βπ₯^2/2β3π₯]_(β6)^(β3) +[π₯^2/2+3π₯]_(β3)^( 0) =[(β(β3)^2)/( 2)β3 Γ (β3)]β[(β(β6)^2)/( 2)β3(β6)] +[0^2/2+3 Γ0]β[(β3)^2/2+3 Γ (β3)] =[(β9)/( 2)β(β9)]β[(β36)/( 2)β(β18)]+[0]β[9/2β9] =(β9)/2+9+0β9/2+9 =β9+18 =π square units