Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Miscellaneous
Misc 1 (ii) Important
Misc 2 Important You are here
Misc 3 Important
Misc 4 (MCQ)
Misc 5 (MCQ) Important
Question 1 Deleted for CBSE Board 2024 Exams
Question 2 Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 4 Deleted for CBSE Board 2024 Exams
Question 5 Deleted for CBSE Board 2024 Exams
Question 6 Important Deleted for CBSE Board 2024 Exams
Question 7 Deleted for CBSE Board 2024 Exams
Question 8 Important Deleted for CBSE Board 2024 Exams
Question 9 Important Deleted for CBSE Board 2024 Exams
Question 10 Deleted for CBSE Board 2024 Exams
Question 11 Important Deleted for CBSE Board 2024 Exams
Question 12 Deleted for CBSE Board 2024 Exams
Question 13 (MCQ) Deleted for CBSE Board 2024 Exams
Question 14 (MCQ) Important Deleted for CBSE Board 2024 Exams
Miscellaneous
Last updated at Aug. 11, 2023 by Teachoo
Misc 2 Sketch the graph of y = |π₯+3| and evaluate β«_(β6)^0βγβπ₯+3β ππ₯γ Letβs Draw the graph y = |π+π| y = |π₯+3| = {β(π₯+3 πππ π₯+3β₯0@β(π₯+3) πππ π₯+3<0 )β€ = {β(π₯+3 πππ π₯β₯β3@β(π₯+3) πππ π₯+3<β3 )β€ Now, Required Area = β«_(βπ)^πβγβπ+πβ π πγ =β«_(β6)^(β3)βγβπ₯+3β ππ₯γ ββ«_(β3)^0βγβπ₯+3β ππ₯γ =β«_(βπ)^(βπ)βγβ(π+π) π π +β«_(βπ)^πβγ(π+π) π πγγ =[βπ₯^2/2β3π₯]_(β6)^(β3) +[π₯^2/2+3π₯]_(β3)^( 0) =[(β(β3)^2)/( 2)β3 Γ (β3)]β[(β(β6)^2)/( 2)β3(β6)] +[0^2/2+3 Γ0]β[(β3)^2/2+3 Γ (β3)] =[(β9)/( 2)β(β9)]β[(β36)/( 2)β(β18)]+[0]β[9/2β9] =(β9)/2+9+0β9/2+9 =β9+18 =π square units