

Subscribe to our Youtube Channel - https://you.tube/teachoo
Last updated at Jan. 23, 2020 by Teachoo
Transcript
Example 11 Prove that |โ 8(๐&๐+๐&๐+๐+๐@2๐&3๐+2๐&4๐+3๐+2๐@3๐&6๐+3๐&10๐+6๐+3๐)| = a3 Let ฮ = |โ 8(๐&๐+๐&๐+๐+๐@2๐&3๐+2๐&4๐+3๐+2๐@3๐&6๐+3๐&10๐+6๐+3๐)| Applying R2 โ R2 โ 2R1 = |โ 8(๐&๐+๐&๐+๐+๐@๐๐โ๐(๐)&3๐+3๐โ2(๐+๐)&4๐+3๐+2๐โ2(๐+๐+๐)@3๐&6๐+3๐&10๐+6๐+3๐)| = |โ 8(๐&๐+๐&๐+๐+๐@๐&3๐+3๐โ2๐โ2๐&4๐+3๐+2๐โ2๐โ2๐โ2๐@3๐&6๐+3๐&10๐+6๐+3๐)| = |โ 8(๐&๐+๐&๐+๐+๐@๐&๐&2๐+๐@3๐&6๐+3๐&10๐+6๐+3๐)| Applying R3 โ R3 โ 3R1 = |โ 8(๐&๐+๐&๐+๐+๐@0&๐&2๐+๐@๐๐โ๐(๐)&6๐+3๐โ3(๐+๐)&10๐+6๐+3๐โ3๐+๐+๐)| = |โ 8(๐&๐+๐&๐+๐+๐@0&๐&2๐+๐@๐&6๐+3๐โ3๐โ3๐&10๐+6๐+3๐โ3๐+๐+๐)| = |โ 8(๐&๐+๐&๐+๐+๐@0&๐&2๐+๐@0&3๐&7๐+3๐)| Expanding along C1 = = a |โ 8(๐&2๐+๐@3๐&7๐+3๐)| โ 0 + 0 = a (a(7a + 3b) โ 3a (2a + b) = a (7a2 + 3ab โ 6a2 โ 3ab) = a(a2) = a3 = R.H.S Hence proved |โ 8(๐&2๐+๐@3๐&7๐+3๐)| |โ 8(๐+๐&๐+๐+๐@3๐&7๐+3๐)|
Examples
Example 2
Example 3
Example 4
Example 5
Example 6 Not in Syllabus - CBSE Exams 2021
Example 7 Not in Syllabus - CBSE Exams 2021
Example 8 Not in Syllabus - CBSE Exams 2021
Example 9 Important Not in Syllabus - CBSE Exams 2021
Example 10 Important Not in Syllabus - CBSE Exams 2021
Example 11 Not in Syllabus - CBSE Exams 2021 You are here
Example 12 Not in Syllabus - CBSE Exams 2021
Example 13 Not in Syllabus - CBSE Exams 2021
Example 14 Important Not in Syllabus - CBSE Exams 2021
Example 15 Important Not in Syllabus - CBSE Exams 2021
Example 16 Important Not in Syllabus - CBSE Exams 2021
Example 17
Example 18 Important
Example 19
Example 20
Example 21
Example 22
Example 23
Example 24 Important
Example 25
Example 26 Important
Example 27 Not in Syllabus - CBSE Exams 2021
Example 28 Important Not in Syllabus - CBSE Exams 2021
Example 29 Not in Syllabus - CBSE Exams 2021
Example 30
Example 31 Important Not in Syllabus - CBSE Exams 2021
Example 32 Important Not in Syllabus - CBSE Exams 2021
Example 33 Important Not in Syllabus - CBSE Exams 2021
Example 34 Important Not in Syllabus - CBSE Exams 2021
About the Author