Example 11 - Chapter 4 Class 12 Determinants
Last updated at May 29, 2018 by Teachoo
Transcript
Example 11 Prove that + + + 2 3 +2 4 +3 +2 3 6 +3 10 +6 +3 = a3 Let = + + + 2 3 +2 4 +3 +2 3 6 +3 10 +6 +3 Applying R2 R2 2R1 = + + + ( ) 3 +3 2( + ) 4 +3 +2 2( + + ) 3 6 +3 10 +6 +3 = + + + 3 +3 2 2 4 +3 +2 2 2 2 3 6 +3 10 +6 +3 = + + + 2 + 3 6 +3 10 +6 +3 Applying R3 R3 3R1 = + + + 0 2 + ( ) 6 +3 3( + ) 10 +6 +3 3 + + = + + + 0 2 + 6 +3 3 3 10 +6 +3 3 + + = + + + 0 2 + 0 3 7 +3 Expanding along C1 = = a 2 + 3 7 +3 0 + 0 = a (a(7a + 3b) 3a (2a + b) = a (7a2 + 3ab 6a2 3ab) = a(a2) = a3 = R.H.S Hence proved
Examples
Example 1
Example 2
Example 3
Example 4
Example 5
Example 6
Example 7
Example 8
Example 9
Example 10
Example 11 You are here
Example 12
Example 13
Example 14 Important
Example 15 Important
Example 16 Important
Example 17
Example 18 Important
Example 19
Example 20
Example 21
Example 22
Example 23
Example 24 Important
Example 25
Example 26 Important
Example 27
Example 28
Example 29
Example 30
Example 31
Example 32 Important
Example 33
Example 34 Important
Chapter 4 Class 12 Determinants
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About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.