Example 5 - Chapter 4 Class 12 Determinants

Last updated at August 13, 2026 by

Example 5 - Find x for which |3 x x 1| = |3 2 4 1| - Examples - Examples

part 2 - Example 5 - Examples - Serial order wise - Chapter 4 Class 12 Determinants

 

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Transcript

Example 5 Find values of x for which |■8(3&x@x&1)| = |■8(3&2@4&1)| Given |■8(3&x@x&1)| = |■8(3&2@4&1)| Putting values 3 – x2 = – 5 – x2 = – 5 – 3 – x2 = – 8 x2 = 8 Calculating |■8(3&x@x&1)| = 3(1) – x (x) = 3 – x2 Calculating |■8(3&2@4&1)| = 3(1) – 4(2) = 3 – 8 = – 5 x = ± √8 = ± √(2" ×" 2" ×" 2) = ± 2√2 Hence value of x is ± 2√𝟐

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