Example 8 - Class 12
Last updated at May 29, 2018 by Teachoo
Transcript
Example 8 Evaluate ∆ = 323223323 First and third row are identical, hence we apply Property 3 ∆ = 323223323 ∆ = 3 2323 – 2 2333 + 3 2232 = 3(2(3) – 2(3)) – 2 (2(3) – 3(3)) + 3 (2 (2) – 3(2)) = 3 (6 – 6) – 2 (6 – 9) + 3 (4 – 6) = 0 + 6 − 6 = 0 ∆ = 0 Here R1 & R3 are identical & the determinant is 0. Thus, if any two rows & columns of determinants are identical , then value of determinant is 0.
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Chapter 4 Class 12 Determinants
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.
