Question 3 Evaluate ∆ = 3﷮2﷮3﷮2﷮2﷮3﷮3﷮2﷮3﷯﷯ First and third row are identical, hence we apply Property 3 ∆ = 3﷮2﷮3﷮2﷮2﷮3﷮3﷮2﷮3﷯﷯ ∆ = 3 2﷮3﷮2﷮3﷯﷯ – 2 2﷮3﷮3﷮3﷯﷯ + 3 2﷮2﷮3﷮2﷯﷯ = 3(2(3) – 2(3)) – 2 (2(3) – 3(3)) + 3 (2 (2) – 3(2)) = 3 (6 – 6) – 2 (6 – 9) + 3 (4 – 6) = 0 + 6 − 6 = 0 ∆ = 0 Here R1 & R3 are identical & the determinant is 0. Thus, if any two rows & columns of determinants are identical , then value of determinant is 0.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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