Exercise 1.12 - The mass of a box measured by a grocer’s balance is - Exercise Questions

part 2 - Exercise 1.12 - Exercise Questions - Chapter 1 - Units and Measurement - Physics Class 11

part 3 - Exercise 1.12 - Exercise Questions - Chapter 1 - Units and Measurement - Physics Class 11

part 4 - Exercise 1.12 - Exercise Questions - Chapter 1 - Units and Measurement - Physics Class 11

Remove Ads
Teachoo Β· Class 11 Explore Class 11

Transcript

Exercise 1.12 The mass of a box measured by a grocer’s balance is 2.30 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box. What is (a) the total mass of the box, (b) the difference in the masses of the pieces to correct significant figures ? Given Mass of box = π’Ž_(𝒃𝒐𝒙) = 2.30 kg Mass of 1^(st) gold piece = π’Ž_(𝟏)= 20.15 g = 20.15 Γ— 10^(–3) kg = 2.015 Γ— 10^(–2) kg Mass of 2^(nd) gold piece = π’Ž_(𝟐) = 20.17 g = 20.17 Γ— 10^(–3) kg = 2.017 Γ— 10^(–2) kg Since we are adding and subtracting here, we write m_(1) and m_(2) in decimals Now, π‘š_(1)= 0.02015 kg π‘š_(2)= 0.02017 kg (a) the total mass of the box, Total mass of box = π‘š_(π‘π‘œπ‘₯) + π‘š_(1) + π‘š_(2) = 2.30 + 0.02015 + 0.02017 = 2.34032 kg Since we are adding numbers, we check lowest decimal places Now, 2.30 has 2 decimal places, so the final answer will have 2 decimal places Thus, Total mass of box = 2.34 kg (b) the difference in the masses of the pieces to correct significant figures ? Now, Difference in gold masses = m_(2) – m_(1) = 0.02017 – 0.02015 = 0.00002 kg Since we are subtracting numbers, we check lowest decimal places Now, both numbers have 5 decimal places, so the final answer will have 5 decimal places Thus, Difference in gold masses = 0.00002 kg Or we can write in grams also Difference in gold masses = m_(2) – m_(1) = 20.17 – 20.15 = 0.02 g Here, we have 2 decimal places in both numbers So, final answer has 2 decimal places = 2.017 Γ— 10^(–2) kg Since we are adding and subtracting here, we write m_(1) and m_(2) in decimals Now, π‘š_(1)= 0.02015 kg π‘š_(2)= 0.02017 kg (a) the total mass of the box, Total mass of box = π‘š_(π‘π‘œπ‘₯) + π‘š_(1) + π‘š_(2) = 2.30 + 0.02015 + 0.02017 = 2.34032 kg Since we are adding numbers, we check lowest decimal places Now, 2.30 has 2 decimal places, so the final answer will have 2 decimal places Thus, Total mass of box = 2.34 kg (b) the difference in the masses of the pieces to correct significant figures ? Now, Difference in gold masses = m_(2) – m_(1) = 0.02017 – 0.02015 = 0.00002 kg Since we are subtracting numbers, we check lowest decimal places Now, both numbers have 5 decimal places, so the final answer will have 5 decimal places Thus, Difference in gold masses = 0.00002 kg Or we can write in grams also Difference in gold masses = m_(2) – m_(1) = 20.17 – 20.15 = 0.02 g Here, we have 2 decimal places in both numbers So, final answer has 2 decimal places

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh holds a B.Tech from the Indian Institute of Technology (IIT), Kanpur, and has been teaching since 2010. At Teachoo, he teaches Maths, Science and Computer Science, drawing on his engineering education and teaching experience to explain concepts and solve questions step by step.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.