Exercise 1.7
Last updated at October 12, 2026 by Teachoo
Exercise Questions
Exercise 1.1
Important
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Transcript
Exercise 1.7 A student measures the thickness of a human hair by looking at it through a microscope of magnification 100. He makes 20 observations and finds that the average width of the hair in the field of view of the microscope is 3.5 mm. What is the estimate on the thickness of hair ? Given Magnification of the microscope (m) = 100 Observed average width of the hair (y) = 3.5 mm Using Magnification Formula π΄ππππππππππππ (π)=(πΆπππππππ πππ ππ (π))/(π¨πππππ πππ ππ (π)) 100=(3.5 ππ)/(π΄ππ‘π’ππ π€πππ‘β (π₯)) Actual width (x) = (3.5 ππ)/(100) Actual width (x) = 0.035 mm Thus, thickness of hair is 0.035 mm Actual width (x) = (3.5 ππ)/(100) Actual width (x) = 0.035 mm Thus, thickness of hair is 0.035 mm
