Β
Last updated at Aug. 28, 2021 by
Β
Transcript
Ex 10.3, 6 Find the distance between parallel lines 15x + 8y β 34 = 0 and 15x + 8y + 31 = 0 We know that , distance between two parallel lines Ax + By + C1 = 0 & Ax + By + C2 = 0 is d = |πΆ_1β πΆ_2 |/β(π΄^2 + π΅^2 ) Equation of first line is 15x + 8y β 34 = 0 Above equation is of the form Ax + By + C1 = 0 where A = 15, B = 8 & C1 = β 34 Equation of second line is 15x + 8y + 31 = 0 Above equation is of the form Ax + By + C2 = 0 where A = 15 , B = 8 , C2 = 31 Distance between parallel lines 15x + 8y β 34 = 0 and 15x + 8y + 31 = 0 is d = |πΆ_1β πΆ_2 |/β(π΄^2 + π΅^2 ) Putting values d = |β34 β 31|/β(γ(15)γ^2 + (8)^2 ) d = |β34 β 31|/β(225 + 64) d = |β65|/β289 d = 65/β(17 Γ 17) d = 65/17 Thus, the required distance is ππ/ππ units
Ex 10.3
Ex 10.3, 1 (ii) Important
Ex 10.3, 1 (iii)
Ex 10.3, 2 (i)
Ex 10.3, 2 (ii)
Ex 10.3, 2 (iii) Important
Ex 10.3, 3 (i)
Ex 10.3, 3 (ii)
Ex 10.3, 3 (iii) Important
Ex 10.3, 4
Ex 10.3, 5 Important
Ex 10.3, 6 (i) Important You are here
Ex 10.3, 6 (ii)
Ex 10.3, 7
Ex 10.3, 8 Important
Ex 10.3, 9 Important
Ex 10.3, 10
Ex 10.3, 11
Ex 10.3, 12 Important
Ex 10.3, 13
Ex 10.3, 14 Important
Ex 10.3, 15
Ex 10.3, 16 Important
Ex 10.3, 17 Important
Ex 10.3, 18 Important
Ex 10.3
About the Author