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Ex 10.3, 6 - Find distance between parallel lines - Class 11

Ex 10.3, 6 - Chapter 10 Class 11 Straight Lines - Part 2
Ex 10.3, 6 - Chapter 10 Class 11 Straight Lines - Part 3

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Ex 9.3, 6 Find the distance between parallel lines 15x + 8y – 34 = 0 and 15x + 8y + 31 = 0 We know that , distance between two parallel lines Ax + By + C1 = 0 & Ax + By + C2 = 0 is d = |𝐢_1βˆ’ 𝐢_2 |/√(𝐴^2 + 𝐡^2 ) Equation of first line is 15x + 8y – 34 = 0 Above equation is of the form Ax + By + C1 = 0 where A = 15, B = 8 & C1 = βˆ’ 34 Equation of second line is 15x + 8y + 31 = 0 Above equation is of the form Ax + By + C2 = 0 where A = 15 , B = 8 , C2 = 31 Distance between parallel lines 15x + 8y – 34 = 0 and 15x + 8y + 31 = 0 is d = |𝐢_1βˆ’ 𝐢_2 |/√(𝐴^2 + 𝐡^2 ) Putting values d = |βˆ’34 βˆ’ 31|/√(γ€–(15)γ€—^2 + (8)^2 ) d = |βˆ’34 βˆ’ 31|/√(225 + 64) d = |βˆ’65|/√289 d = 65/√(17 Γ— 17) d = 65/17 Thus, the required distance is πŸ”πŸ“/πŸπŸ• units

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.