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Ex 9.3, 6 Find the distance between parallel lines (ii) 𝑙(x + y) + p = 0 and 𝑙(x + y) – r = 0 We know that, distance between two parallel lines Ax + By + C1 = 0 & Ax + By + C2 = 0 is d = |𝐶_1 − 𝐶_2 |/√(𝐴^2 + 𝐵^2 ) Equation of the first line is 𝑙(x + y) + p = 0 𝑙x + 𝑙y + p = 0 Above equation is of the form Ax + By + C1 = 0 where A = 𝑙 , B = 𝑙 & C1 = p Equation of the second line is 𝑙(x + y) − r = 0 𝑙x + ly – r = 0 The above equation is of the form Ax + By + C2 = 0 where A = 𝑙 , B = 𝑙 , C2 = −r Distance between parallel lines 𝑙(x + y) + p = 0 & 𝑙(x + y) − r = 0 is d = |𝐶_1 − 𝐶_2 |/√(𝐴^2 + 𝐵^2 ) Putting values d = |𝑝 − (−𝑟)|/√(𝑙^2 + 𝑙^2 ) d = |𝑝 + 𝑟|/√(2𝑙^2 ) d = (|𝑝 + 𝑟| )/(|𝑙|√2) d = |(𝑝 + 𝑟 )/(𝑙√2)| Thus, the required distance is |(𝒑 + 𝒓 )/(𝒍√𝟐)| units

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.