Ex 10.3, 3 - Chapter 10 Class 11 Straight Lines - Part 6

Ex 10.3, 3 - Chapter 10 Class 11 Straight Lines - Part 7
Ex 10.3, 3 - Chapter 10 Class 11 Straight Lines - Part 8

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Transcript

Ex10.3, 3 Reduce the following equations into normal form. Find their perpendicular distances from the origin and angle between perpendicular and the positive x-axis. (iii) x y = 4 x y = 4 Dividing both side by (12 + ( 1)2)= (1 + 1)= 2 ( )/ 2 = 4/ 2 ( )/ 2 = 4/ 2 2/ 2 ( )/ 2 = (4 2)/2 / 2 ( )/ 2 = 2 2 x(1/ 2) + y(( 1)/ 2) = 2 2 Normal form of any line is x cos + y sin = p Comparing (1) & (2) p = 2 2 & cos = 1/ 2 & sin = ( 1)/ 2 Finding = 360 45 = 315 Thus, the normal form of line is x cos 315 + y sin 315 = 2 2 Hence, perpendicular distance from origin = p = 2 2 & angle between perpendicular & the + ve x-axis = = 315

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.