![Ex 10.3, 3 - Chapter 10 Class 11 Straight Lines - Part 5](https://d1avenlh0i1xmr.cloudfront.net/cf4f2895-4c75-4475-ad0b-93b605755545/slide16.jpg)
Ex 9.3
Last updated at April 16, 2024 by Teachoo
Ex10.3, 3 Reduce the following equations into normal form. Find their perpendicular distances from the origin and angle between perpendicular and the positive x-axis. (ii) y 2 = 0 y 2 = 0 0x + y 2 = 0 0x + y = 2 Dividing both side by (02 + 12) = (0 + 1) = 1 (0 + )/1 = 2/1 0x + y = 2 The normal form of any line is x cos + y sin = p Comparing (1) & (2) p = 2 and cos = 0 & sin = 1 We know that cos 90 = 0 and sin 90 = 1 Thus, = 90 So, = 90 & p = 2 Thus, the normal form of line is x cos 90 + y sin 90 = 2 Hence, perpendicular distance from origin = p = 2 & angle between perpendicular & the + ve x-axis = = 90