Last updated at Aug. 28, 2021 by
Transcript
Ex10.3, 3 Reduce the following equations into normal form. Find their perpendicular distances from the origin and angle between perpendicular and the positive x-axis. (ii) y 2 = 0 y 2 = 0 0x + y 2 = 0 0x + y = 2 Dividing both side by (02 + 12) = (0 + 1) = 1 (0 + )/1 = 2/1 0x + y = 2 The normal form of any line is x cos + y sin = p Comparing (1) & (2) p = 2 and cos = 0 & sin = 1 We know that cos 90 = 0 and sin 90 = 1 Thus, = 90 So, = 90 & p = 2 Thus, the normal form of line is x cos 90 + y sin 90 = 2 Hence, perpendicular distance from origin = p = 2 & angle between perpendicular & the + ve x-axis = = 90
Ex 10.3
Ex 10.3, 1 (ii) Important
Ex 10.3, 1 (iii)
Ex 10.3, 2 (i)
Ex 10.3, 2 (ii)
Ex 10.3, 2 (iii) Important
Ex 10.3, 3 (i)
Ex 10.3, 3 (ii) You are here
Ex 10.3, 3 (iii) Important
Ex 10.3, 4
Ex 10.3, 5 Important
Ex 10.3, 6 (i) Important
Ex 10.3, 6 (ii)
Ex 10.3, 7
Ex 10.3, 8 Important
Ex 10.3, 9 Important
Ex 10.3, 10
Ex 10.3, 11
Ex 10.3, 12 Important
Ex 10.3, 13
Ex 10.3, 14 Important
Ex 10.3, 15
Ex 10.3, 16 Important
Ex 10.3, 17 Important
Ex 10.3, 18 Important
Ex 10.3
About the Author