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Ex 10.3, 2 - Reduce equations into intercept form - CBSE - Ex 10.3

  1. Chapter 10 Class 11 Straight Lines
  2. Serial order wise
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Ex10.3, 2 Reduce the following equations into intercept form and find their intercepts on the axes. 3x + 2y – 12 = 0 . 3x + 2y – 12 = 0 3x + 2y = 0 + 12 3x + 2y = 12 Dividing both sides by 12 (3x + 2y)/12 = 12/12 3𝑥/12 + 2𝑦/12 = 1 𝑥/4 + 𝑦/6 = 1 The above equation is of the form 𝑥/𝑎 + 𝑦/𝑏 = 1 where x-intercept = a = 4 & y-intercept = b = 6 Ex10.3, 2 Reduce the following equations into intercept form and find their intercepts on the axes. (ii) 4x – 3y = 6 4x – 3y = 6 Dividing both side by 6 (4𝑥 − 3𝑦)/6 = 6/6 4𝑥/6 − 3𝑦/6 = 1 2𝑥/3 − 𝑦/2 = 1 𝑥/((3/2) ) + 𝑦/(( − 2) ) = 1 The above equation is of the form 𝑥/𝑎 + 𝑦/𝑏 = c Where x-intercept = a = 3/2 & y-intercept = b = –2 Ex10.3, 2 Reduce the following equations into intercept form and find their intercepts on the axes. (iii) 3y + 2 = 0. 3y + 2 = 0 3y = − 2 Divide both sides by −2 3𝑦/( − 2) = ( − 2)/( − 2) 3𝑦/( − 2) = 1 𝑦/(( − 2/3) ) = 1 The above equation is of the form 𝑥/𝑎 + 𝑦/𝑏 = 1 where x-intercept = a = No intercept as there is no x & y-intercept = b = − 2/3

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