This question is similar to Chapter 6 Class 10 Triangles - Ex 6.3

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https://www.teachoo.com/1678/519/Ex-6.3--16---If-AD-and-PM-are-medians-of-triangles-ABC--PQR/category/Ex-6.3/

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Question 23 If AP and DQ are medians of triangles ABC and DEF respectively, where β–³ABCβˆΌβ–³DEF, then prove that 𝐴𝐡/𝐷𝐸=𝐴𝑃/𝐷𝑄 Given: Ξ”ABC and Ξ”DEF AP is the median of Ξ” ABC & DQ is the median of Ξ” DEF & Ξ”ABC ∼ Ξ” DEF To Prove:- 𝐴𝐡/𝐷𝐸=𝐴𝑃/𝐷𝑄 Proof: Since AP is the median BP = CP = 𝟏/𝟐 BC Similarly, DQ is the median EQ = FQ = 𝟏/𝟐 EF Since Ξ”ABC ∼ DEF And, Corresponding sides of Similar Triangle are proportional 𝑨𝑩/𝑫𝑬=𝑩π‘ͺ/𝑬𝑭=𝑨π‘ͺ/𝑷𝑹 So, we can write 𝐴𝐡/𝐷𝐸=𝐡𝐢/𝐸𝐹 Putting BC = 2 Γ— BP and EF = 2 Γ— EQ 𝐴𝐡/𝐷𝐸=2𝐡𝑃/2𝐸𝑄 𝑨𝑩/𝑫𝑬=𝑩𝑷/𝑬𝑸 Also, since Ξ”ABC ∼ Ξ”DEF And, angles of similar triangle are equal ∠ B = ∠ E Now, In Ξ” ABP & Ξ”DEQ ∠𝐡=βˆ π‘„ 𝐴𝐡/𝐷𝐸=𝐡𝑃/𝐸𝑄 Hence by SAS similarly Ξ”ABP ∼ Ξ”DEQ Since corresponding sides of similar triangles are proportional ∴ 𝑨𝑩/𝑷𝑸=𝑨𝑫/𝑷𝑴 Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo