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If △ABC∼△DEF,AB=6 cm,DE=9 cm,EF=6 cm and FD=12 cm, then the perimeter - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard

part 2 - Question 14 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 14 If △ABC∼△DEF,AB=6" " cm,DE=9" " cm,EF=6" " cm and FD=12" " cm, then the perimeter of △ABC is (A) 28 cm (B) 28.5 cm (C) 18 cm (D) 23 cm Since ∆ ABC ~ ∆ DEF Sides will be proportional 𝐀𝐁/𝐃𝐄=𝑩𝑪/𝑬𝑭=𝑨𝑪/𝑫𝑭 Putting values 6/9=𝐵𝐶/6=𝐴𝐶/12 𝟐/𝟑=𝑩𝑪/𝟔=𝑨𝑪/𝟏𝟐 Now, Perimeter of Δ ABC = AB + BC + CD = 6 + 4 + 8 = 18 cm So, the correct answer is (c) 𝑩𝑪/𝟔=𝟐/𝟑 BC = 𝟐/𝟑 × 6 BC = 4 cm 𝟐/𝟑=𝑨𝑪/𝟏𝟐 AC = 𝟐/𝟑 × 12 AC = 8 cm

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo