∆ABC is such that AB = 3 cm, BC = 2cm, CA = 2.5 cm. If ∆ABC ~ ∆DEF and EF = 4 cm, then perimeter of ∆DEF is
(a) 7.5 cm (b) 15 cm (c) 22.5 cm (d) 30 cm
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Last updated at Sept. 6, 2021 by Teachoo
Transcript
Question 16 ∆ABC is such that AB = 3 cm, BC = 2cm, CA = 2.5 cm. If ∆ABC ~ ∆DEF and EF = 4 cm, then perimeter of ∆DEF is (a) 7.5 cm (b) 15 cm (c) 22.5 cm (d) 30 cm Since ∆ ABC ~ ∆ DEF Sides will be proportional AB/DE=𝐵𝐶/𝐸𝐹=𝐴𝐶/𝐸𝐹 Putting values 3/DE=2/4=2.5/𝐸𝐹 3/DE=1/2=2.5/𝐸𝐹 𝟑/𝑫𝑬=𝟏/𝟐 DE = 2 × 3 DE = 6 cm 𝟏/𝟐=(𝟐.𝟓)/𝑬𝑭 EF = 2 × 2.5 EF = 5 cm Now, Perimeter of Δ DEF = DE + EF + DF = 6 + 5 + 4 = 15 cm So, the correct answer is (b)
CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]
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CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]
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