Question 19 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards

Last updated at August 12, 2026 by Teachoo

One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be

(a) 10x + 14y + 4 = 0 (b) –10x – 14y + 4 = 0

(c) –10x + 14y + 4 = 0 (d) 10x – 14y = –4

This question is inspired from Question 11 - MCQs from NCERT Exemplar - Chapter 3 Class 10 - Pair of Linear Equations in Two Variables

Ques 19 (MCQ) - One equation of a pair of dependent linear equations - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]

part 2 - Question 19 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

Question 19 One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be (a) 10x + 14y + 4 = 0 (b) –10x – 14y + 4 = 0 (c) –10x + 14y + 4 = 0 (d) 10x – 14y = –4 Given equation −5x + 7y − 2 = 0 Therefore, a1 = −5, b1 = 7 , c1 = –2 Since we want a dependent line, it means the lines are coincident For Coincident lines 𝒂𝟏/𝒂𝟐 = 𝒃𝟏/𝒃𝟐 = 𝒄𝟏/𝒄𝟐 Since, a1 = −5 , b1 = 7 , c1 = −2 a2, b2, c2 can be a2 = −10 , b2 = 14 , c2 = −4 Thus, a coincident line is −10x + 14y − 4 = 0 10x − 14y = −4 So, the correct answer is (D)

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