Question 19 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards
Last updated at Sept. 6, 2021 by Teachoo

One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be
(a) 10x + 14y + 4 = 0 (b) –10x – 14y + 4 = 0
(c) –10x + 14y + 4 = 0 (d) 10x – 14y = –4

This question is
inspired from
Question 11 - MCQs from NCERT Exemplar
- Chapter 3 Class 10 -
Pair of Linear Equations in Two Variables

Transcript

Question 19 One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be (a) 10x + 14y + 4 = 0 (b) –10x – 14y + 4 = 0 (c) –10x + 14y + 4 = 0 (d) 10x – 14y = –4
Given equation
−5x + 7y − 2 = 0
Therefore,
a1 = −5, b1 = 7 , c1 = –2
Since we want a dependent line,
it means the lines are coincident
For Coincident lines
𝒂𝟏/𝒂𝟐 = 𝒃𝟏/𝒃𝟐 = 𝒄𝟏/𝒄𝟐
Since, a1 = −5 , b1 = 7 , c1 = −2
a2, b2, c2 can be
a2 = −10 , b2 = 14 , c2 = −4
Thus, a coincident line is
−10x + 14y − 4 = 0
10x − 14y = −4
So, the correct answer is (D)

Show More