∆ABC ~ ∆PQR. If AM and PN are altitudes of ∆ABC and ∆PQR respectively and AB2 : PQ2 = 4 : 9, then AM : PN =

(a) 16 : 81   (b) 4 : 9   (c) 3 : 2   (d) 2 : 3

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Question 6 ∆ABC ~ ∆PQR. If AM and PN are altitudes of ∆ABC and ∆PQR respectively and AB2 : PQ2 = 4 : 9, then AM : PN = (a) 16 : 81 (b) 4 : 9 (c) 3 : 2 (d) 2 : 3 Given AB2 : PQ2 = 4 : 9 (𝐴𝐵^2)/(𝑃𝑄^2 )=4/9 (𝐴𝐵/𝑃𝑄)^2=(2/3)^2 𝑨𝑩/𝑷𝑸=𝟐/𝟑 Now, When two triangles are similar Ratio of their altitudes = Ratio of their sides Thus, 𝑨𝑴/𝑷𝑵=" " 𝑨𝑩/𝑷𝑸 𝑨𝑩/𝑷𝑸=𝟐/𝟑 So, the correct answer is (d)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.