The zeroes of the polynomial r(t) = −12t 2 + (k − 3)t + 48 are negative of each other. Then k is

(a) 3   (b) 0   (c) −1.5   (d) −3

Ques 45 (Case Based) - The zeroes of the polynomial r(t) = -12t^2 + (k - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]

part 2 - Question 45 (Case Based Question) - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 45 The zeroes of the polynomial r(t) = −12t2 + (k − 3)t + 48 are negative of each other. Then k is (a) 3 (b) 0 (c) −1.5 (d) −3 Given r(t) = −12t2 + (k − 3)t + 48 Since zeros are negative of each other Let zeroes of r(t) be 𝛼 and −𝛼 Now, Sum of Zeroes = (−𝑏)/𝑎 0 = (−(𝒌 − 𝟑))/(−𝟏𝟐) 0 = ((𝑘 − 3))/12 0 = k − 3 3 = k k = 3 So, the correct answer is (a)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo