Question 30 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards

Last updated at Sept. 7, 2021 by

In the given figure, ∠ACB = ∠CDA, AC = 8cm, AD = 3cm, then BD is

(a) 22/3 cm (b) 26/3 cm (c) 55/3 cm (d) 64/3 cm

This question is inspired from Question 17 - Sample Paper for 2020 Boards - Class 10 Sample Paper

Transcript

Question 30 In the given figure, ∠ACB = ∠CDA, AC = 8cm, AD = 3cm, then BD is (a) 22/3 cm (b) 26/3 cm (c) 55/3 cm (d) 64/3 cm Given ∠ACB = ∠CDA In Δ ACB and Δ ADC ∠ACB = ∠ADC ∠CAB = ∠DAC ∴ Δ ACB ∼ Δ ADC We know that Sides of similar triangle are in same proportion ∴ 𝐴𝐶/𝐴𝐷 = 𝐴𝐵/𝐴𝐶 Putting values 8/3 = 𝐴𝐵/8 8/3 = 𝐴𝐵/8 8/3 × 8 = AB 64/3 = AB AB = 𝟔𝟒/𝟑 Now, BD = AB − AD = 64/3 − 3 = (64 − 9)/3 = 𝟓𝟓/𝟑 cm So, the correct answer is (c)

CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]

Question 30 You are here

CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ] →

Class 10

Solutions of Sample Papers for Class 10 Boards

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.