If 4 tan β = 3, then (4 sinβ - 3 cosβ)/(4 sinβ + 3 cosβ ) =
(a) 0 (b) 1/3 (c) 2/3 (d) 3/4
This question is inspired from Question 15 - NCERT Exemplar - MCQ - Chapter 8 Class 10 - Introduction to Trignometry
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Last updated at Sept. 6, 2021 by Teachoo
This question is inspired from Question 15 - NCERT Exemplar - MCQ - Chapter 8 Class 10 - Introduction to Trignometry
Transcript
Question 18 If 4 tan β = 3, then (4 sin𝛽 − 3 cos𝛽)/(4 sin𝛽 + 3 cos𝛽 ) = (a) 0 (b) 1/3 (c) 2/3 (d) 3/4 Given 4 tan β = 3 tan β = 𝟑/𝟒 Now, (4 sin〖𝛽 − 3 cos𝛽 〗)/(4 sin〖𝛽 + 〖3 cos〗𝛽 〗 ) Dividing numerator and denominator by cos θ = (4 sin𝛽/cos𝛽 − 3 cos𝛽/cos𝛽 )/(4 sin𝛽/cos𝛽 + 3 cos𝛽/cos𝛽 ) = (𝟒 𝐭𝐚𝐧〖𝛽 − 𝟑〗)/(𝟒 𝐭𝐚𝐧〖𝜽 + 𝟑〗 ) Putting tan 𝛽 = 𝟑/𝟒 = (4 × 3/4 − 3)/(4 × 3/4 + 3) = (3 − 3)/(3 + 3) = 0/6 = 0 So, the correct answer is (a)
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CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]
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