This question is similar to Chapter 13 Class 10 Statistics - Ex 13.3

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Question 35 (A) - Find the mean and median of the data: Class 85-90 - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard

part 2 - Question 35 (A) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 35 (A) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10 part 4 - Question 35 (A) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10 part 5 - Question 35 (A) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

Question 35 (A) Find the mean and median of the following data: Let’s first find median Finding Median Median = l + (𝑁/2 βˆ’π‘π‘“)/𝑓 Γ— h Here, 𝑡/𝟐 ∴ 100 – 105 is the median class And, l = lower limit of median class h = class-interval cf = cumulative frequency of the class before median class f = frequency of the median class Putting values in formula Median = l + (𝑁/2 βˆ’π‘π‘“)/𝑓 Γ— h = 100 + (πŸ”πŸŽ βˆ’ πŸ“πŸ•)/πŸπŸ– Γ— 5 = 100 + 3/18 Γ— 5 = 100 + 5/6 = 100 + 0.83 = 100.83 Now, let’s find Mean Finding Mean Mean(π‘₯ Μ…) = a + h Γ— (βˆ‘β–’π’‡π’Šπ’–π’Š)/(βˆ‘β–’π’‡π’Š) Where a = assumed mean h = Class interval Also, βˆ‘β–’π’‡π’Š = 120 βˆ‘β–’π’‡π’Šπ’–π’Š = βˆ’39 Putting values in formula Mean(𝒙 Μ…) = a + h Γ— (βˆ‘β–’π’‡π’Šπ’–π’Š)/(βˆ‘β–’π’‡π’Š) π‘₯ Μ… = 102.5 + 5 Γ— (βˆ’39)/120 π‘₯ Μ… = 102.5 βˆ’ 39/24 = 102.5 βˆ’ 13/8 = 102.5 βˆ’ 1.625 𝒙 Μ… = 100.875 Therefore, Mean is 100.875

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