CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard
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CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard
Last updated at August 6, 2026 by Teachoo
This question is similar to Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Ex 3.1
Please check the question here
![[Class 10] Solve linear equations graphically: x+2y = 3, 2x-3y+8 = 0 - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard](https://cdn.teachoo.com/137b83d9-0045-4417-ad06-812ab7eb60ac/slide95.jpg)
Transcript
Question 32 (A) Solve the following system of linear equations graphically: x+2y = 3, 2x-3y+8 = 0Our equations are x + 2y = 3 2x − 3y = −8 For Equation (1) x + 2y = 3 Putting x = 0 0 + 2y = 3 2y = 3 y = 3/2 y = 1.5 So, x = 0, y = 1.5 is a solution i.e. (0, 1.5) is a solution Putting y = 0 x + 2(0) = 3 x + 0 = 3 x = 3 So, x = 3, y = 0 is a solution i.e. (3, 0) is a solution For Equation (2) 2x − 3y = −8 Putting x = 0 2(0) − 3y = −8 −3y = −8 y = (−8)/(−3) y = 2.67 So, x = 0, y = 2.67 is a solution i.e. (0, 2.67) is a solution Putting y = 0 2x − 3(0) = −8 2x = −8 x = (−8)/2 x = −4 So, x = −4, y = 0 is a solution i.e. (−4, 0) is a solution We will plot both equations on the graph Since lines intersect at (−1, 2) ∴ x = −1, y = 2 is the solution of the pair of equations
