Question 38 (iii) (B) - Find the total capacity of one silo to store - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard

part 2 - Question 38 (iii) (B) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 38 (iii) (B) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

 

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Question 38 (iii) (B) Find the total capacity of one silo to store grains.Total capacity of silo is total volume Now, Total capacity = Volume of cone + Volume of Cylinder = 1/3 šœ‹ (š‘…š‘Žš‘‘š‘–š‘¢š‘  š‘œš‘“ š‘š‘œš‘›š‘’)^2 Ɨ š»š‘’š‘–š‘”ā„Žš‘” š‘œš‘“ š‘š‘œš‘›š‘’ + šœ‹(š‘…š‘Žš‘‘š‘–š‘¢š‘  š‘œš‘“ š‘š‘¦š‘™š‘–š‘›š‘‘š‘’š‘Ÿ)^2 Ɨ š»š‘’š‘–š‘”ā„Žš‘” š‘œš‘“ š‘š‘¦š‘™š‘–š‘›š‘‘š‘’š‘Ÿ = šŸ/šŸ‘ š… Ɨ (šŸ.šŸ“)^šŸ Ɨ šŸ+š… Ɨ (šŸ.šŸ“)^šŸ Ɨ šŸ• = šœ‹ Ɨ (1.5)^2 [1/3Ɨ 2+7] = 22/7Ɨ (3/2)^2 [(2 + 7 Ɨ 3)/3] = 22/7Ɨ (3/2)^2 [(2 + 21)/3] = 22/7Ɨ (3/2)^2 [23/3] = 22/7Ɨ3/2 Ɨ3/2 Ɨ23/3 = 11/7Ɨ1/1 Ɨ3/2 Ɨ23/1 = 759/14 = 54.21 m3

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