Question 37 (ii) - If DP= 50 cm and PE = 70 cm then find PQ/EF - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard

part 2 - Question 37 (ii) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 37 (ii) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 37 (ii) (ii) If DP = 50 cm and PE = 70 cm then find 𝑃𝑄/𝐸𝐹.Since Ξ” DPQ ~ Ξ” DEF And, we know that Sides of similar triangles are proportional Therefore, 𝑫𝑷/𝑫𝑬=𝑷𝑸/𝑬𝑭 Since we know DP and PE, putting DE = DP + PE 𝐷𝑃/(𝐷𝑃 + 𝑃𝐸)=𝑃𝑄/𝐸𝐹 Putting DP = 50 cm and PE = 70 cm 50/(50 + 70)=𝑃𝑄/𝐸𝐹 50/120=𝑃𝑄/𝐸𝐹 5/12=𝑃𝑄/𝐸𝐹 𝑷𝑸/𝑬𝑭=πŸ“/𝟏𝟐

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