Question 21 (B) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Feb. 12, 2025 by Teachoo

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The H.C.F of 85 and 238 is expressible in the form 85m -238 [Video] - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard

part 2 - Question 21 (B) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 21 (B) The H.C.F of 85 and 238 is expressible in the form 85m − 238. Find the value of m.To find HCF of 85 and 238, We do prime factorization of both 85 = 5 × 17 238 = 2 × 7 × 17 ∴ HCF = 17 Writing HCF in terms of 85m − 238 HCF = 85m − 238 17 = 85m − 238 17 + 238 = 85m 255 = 85m 85m = 255 m = 255/85 m = 3

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo

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