Examples

Example 1

Example 2 Important

Example 3

Example 4

Example 5 Important

Example 6

Example 7 Important

Example 8 Important

Example 9 Important Deleted for CBSE Board 2023 Exams

Example 10 Important Deleted for CBSE Board 2023 Exams

Example 11 Deleted for CBSE Board 2023 Exams

Example 12 Deleted for CBSE Board 2023 Exams You are here

Example 13 Important Deleted for CBSE Board 2023 Exams

Example 14 Important Deleted for CBSE Board 2023 Exams

Chapter 6 Class 10 Triangles

Serial order wise

Last updated at May 29, 2018 by Teachoo

Example 12 In figure, if AD BC, prove that AB2 + CD2 = BD2 + AC2. Given: where AD BC To Prove:- AB2 + CD2 = BD2 + AC2 Proof: Since AC BD ADC = ADB = 90 Doing (1) (2) AB2 AC2 = (AD2 + BD2) (AD2 + CD2) AB2 AC2 = AD2 + BD2 AD2 CD2 AB2 AC2 = BD2 CD2 AB2 + CD2 = BD2 + AC2 Hence proved