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Example 5 - Chapter 6 Class 10 Triangles (Term 1)

Last updated at March 29, 2023 by

Example 5 - Observe figure and then find angle P. - SSS Similarity

Example 5 - Chapter 6 Class 10 Triangles - Part 2
Example 5 - Chapter 6 Class 10 Triangles - Part 3

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Example 5 Observe figure and then find P. Given: AB = 3.8 , PQ = 6 3 , BC = 6 , QR = 12 , AC = 3 3 , PR = 7.6 To find:- angle P i.e. P Solution:- in Let us find the ratio of sides / =3.8/7.6 = 38/76 = 1/2 / =(3 3)/(6 3)=1/2 / =6/12= 1/2 Thus, / = / = / (Using SSS similarity criterion) So , ~ Now we need to find P We know that corresponding angles of similar triangle are equal . Therefore, C = P In A + B + C = 180 80 +60 + C = 180 140 + C = 180 C = 180 140 C = 40 Thus, C = 40 Hence , P = C = 40

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.