

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Examples
Example 2 Important
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Important
Example 8 Important
Question 10 Important Deleted for CBSE Board 2024 Exams You are here
Question 2 Important Deleted for CBSE Board 2024 Exams
Question 3 Deleted for CBSE Board 2024 Exams
Question 1 Deleted for CBSE Board 2024 Exams
Question 6 Important Deleted for CBSE Board 2024 Exams
Question 10 Important Deleted for CBSE Board 2024 Exams You are here
Last updated at May 29, 2023 by Teachoo
Question 1 In figure, the line segment XY is parallel to side AC of ABC and it divides the triangle into two parts of equal areas. Find the ratio / Given: ABC XY is parallel to AC i.e. XY II AC ar( BXY ) = ar(AXYC) To find : / Proof: In ABC & XBY, ABC = XBY ACB = XYB ABC ~ XBY ABC ~ XBY Now, we know that in similar triangles, Ratio of area of triangle is equal to ratio of square of corresponding sides ( )/( )=( / )^2 ( + )/( )=( / )^2 ( + )/( )=( / )^2 (2 )/( )=( / )^2 2=( / )^2 ( / )^2 = 2 / = 2 / 2= XB XB = / 2 Now, we need to find / Since, AX + XB = AB AX + / 2 = AB AX = AB / 2 AX = AB (1 1/ 2) / = ( 2 1)/ 2 Hence , / =( 2 1)/ 2