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Ex 6.6, 1 (Optional) - PS is bisector of angle QPR of PQR. Prove QS/SR

Ex 6.6, 1 (Optional) - Chapter 6 Class 10 Triangles - Part 2
Ex 6.6, 1 (Optional) - Chapter 6 Class 10 Triangles - Part 3 Ex 6.6, 1 (Optional) - Chapter 6 Class 10 Triangles - Part 4

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Ex 6.6, 1 In Fig. 6.56, PS is the bisector of QPR of PQR. Prove that / = / Given : PQR and PS is the bisector of QPR i.e. QPS = RPS To Prove: / = / Construction : Draw RT SP such that RT cuts QP Produced at T. Proof: In QRT, RT SP and PS intersects QT and QR at two distinct points P and Q Therefore, applying Basic Proportionality Theorem in QRT QT and QR will be divided in the same ratio / = / Now, we need to prove PT = PR Now RT SP & PR is the transversal Therefore, Also, Given that PS is the bisector of QPR QPS = RPS 1 = 2 Putting 1 = 4 and 2 = 3 from (2) & (3) 4 = 3 i.e. PTR = PRT Therefore, PT = PR Putting PT = PR in equation (1) / = / / = / Hence Proved.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.