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  1. Chapter 6 Class 10 Triangles
  2. Serial order wise
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Ex 6.6, 7 In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that : Δ APC ∼ Δ DPB Given: A Circle with two chords AB and CD intersecting at point P To Prove: (i) ∆APC ∼ ∆DPB Proof: In ∆APC and ∆DPB ∠APC = ∠DPB ∠CAP = ∠BDP ∴ ∆ APC ∼ ∆DPB Hence Proved. Ex 6.6, 7 In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that : (ii) AP . PB = CP . DP From part (i) ∆APC ∼ ∆DPB Thus, 𝐴𝑃/𝐷𝑃 = 𝐶𝑃/𝐵𝑃 AP . BP = CP . DP Hence Proved

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CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 7 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .
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