Vijay is trying to find the average height of a tower near his house. He is using the properties of similar triangles.The height of Vijay’s house if 20m when Vijay’s house casts a shadow 10m long on the ground. At the same time, the tower casts a shadow 50m long on the ground and the house of Ajay casts 20m shadow on the
ground.

Vijay is trying to find the average - Teachoo.jpg

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Question 1

What is the height of the tower?
(a) 20 m
(b) 50 m
(c) 100 m
(d) 200 m

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Question 2

What will be the length of the shadow of the tower when Vijay’s house casts a shadow of 12m?
(a) 75 m
(b) 50 m
(c) 45 m
(d) 60 m

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Question 3

What is the height of Ajay’s house?
(a) 30 m
(b) 40 m
(c) 50 m
(d) 20m

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Question 4

When the tower casts a shadow of 40m, same time what will be the length of the shadow of Ajay’s house?
(a) 16 m
(b) 32 m
(c) 20 m
(d) 8 m

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Question 5

When the tower casts a shadow of 40m, same time what will be the length of the shadow of Vijay’s house?
(a) 15 m
(b) 32 m
(c) 16 m
(d) 8 m

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Transcript

Question Vijay is trying to find the average height of a tower near his house. He is using the properties of similar triangles.The height of Vijay’s house if 20m when Vijay’s house casts a shadow 10m long on the ground. At the same time, the tower casts a shadow 50m long on the ground and the house of Ajay casts 20m shadow on the ground. Question 1 What is the height of the tower? (a) 20 m (b) 50 m (c) 100 m (d) 200 m Since the triangles are similar Their sides are proportional (π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘½π’Šπ’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘½π’Šπ’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)=(π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘»π’π’˜π’†π’“)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘»π’π’˜π’†π’“) 20/10=(π»π‘’π‘–π‘”β„Žπ‘‘ π‘œπ‘“ π‘‡π‘œπ‘€π‘’π‘Ÿ)/50 50 Γ— 2 = Height of Tower Height of Tower = 100 m So, the correct answer is (c) Question 2 What will be the length of the shadow of the tower when Vijay’s house casts a shadow of 12 m? (a) 75 m (b) 50 m (c) 45 m (d) 60 m If Vijay’s house casts a shadow of 12 m, Then (π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘½π’Šπ’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘½π’Šπ’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)=(π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘»π’π’˜π’†π’“)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘»π’π’˜π’†π’“) 20/12=100/(πΏπ‘’π‘›π‘”π‘‘β„Ž π‘œπ‘“ π‘ β„Žπ‘Žπ‘‘π‘œπ‘€ π‘œπ‘“ π‘‡π‘œπ‘€π‘’π‘Ÿ) Length of shadow of tower = 100 Γ— 12/20 Length of shadow of tower = 5 Γ— 12 Length of shadow of tower = 60 m So, the correct answer is (d) Question 3 What is the height of Ajay’s house? (a) 30 m (b) 40 m (c) 50 m (d) 20m Since the triangles are similar Their sides are proportional (π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘½π’Šπ’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘½π’Šπ’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)=(π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘¨π’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘¨π’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆) 20/10=(π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘¨π’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)/20 20 Γ— 2 = Height of Ajay’s house Height of Ajay’s house = 40 m So, the correct answer is (b) Question 4 When the tower casts a shadow of 40m, same time what will be the length of the shadow of Ajay’s house? (a) 16 m (b) 32 m (c) 20 m (d) 8 m Since the triangles are similar Their sides are proportional (π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘»π’π’˜π’†π’“)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘»π’π’˜π’†π’“)=(π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘¨π’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘¨π’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆) 100/40=πŸ’πŸŽ/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘¨π’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆) Length of shadow of Ajay’s house = 40 Γ— 40/100 Length of shadow of Ajay’s house = 4 Γ— 4 Length of shadow of Ajay’s house = 16 m So, the correct answer is (a) Question 5 When the tower casts a shadow of 40m, same time what will be the length of the shadow of Vijay’s house? (a) 15 m (b) 32 m (c) 16 m (d) 8 m Since the triangles are similar Their sides are proportional (π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘»π’π’˜π’†π’“)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘»π’π’˜π’†π’“)=(π‘―π’†π’Šπ’ˆπ’‰π’• 𝒐𝒇 π‘½π’Šπ’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆)/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘½π’Šπ’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆) 100/40=𝟐𝟎/(π‘³π’†π’π’ˆπ’•π’‰ 𝒐𝒇 π’”π’‰π’‚π’…π’π’˜ 𝒐𝒇 π‘½π’Šπ’‹π’‚π’š^β€² 𝒔 𝒉𝒐𝒖𝒔𝒆) Length of shadow of Vijay’s house = 20 Γ— 40/100 Length of shadow of Vijay’s house = 2 Γ— 4 Length of shadow of Vijay’s house = 8 m So, the correct answer is (d)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.