Question 5 - Case Based Questions (MCQ) - Chapter 6 Class 10 Triangles

Transcript

Question An aeroplane leaves an airport and flies due north at a speed of 1000 km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1200 km per hour. We know that Speed = (𝐷𝑖𝑠𝑡𝑎𝑛𝑐𝑒 )/𝑇𝑖𝑚𝑒 Distance = Speed × Time Thus, OA = 1500 km & OB = 1800 km Question 1 What is the distance travelled by aeroplane towards north after 11/2 hours? (a) 1000 (b) 1200 (c) 1500 (d) 1800 Distance travelled towards north = OA = 1500 km So, the correct answer is (c) Question 2 What is the distance travelled by aeroplane towards west after 11/2 hours? (a) 1000 (b) 1200 (c) 1500 (d) 1800 Distance travelled towards north = OB = 1800 km So, the correct answer is (d) Question 3 ∠ AOB is (a) 90° (b) 45° (c) 30° (d) 60° Since North is always perpendicular to West Hence, ∠AOB = 90° So, the correct answer is (c) Question 4 How far apart will the two planes be after 1 1/2 hours? (a) √22,50,000 (b) √32,40,000 (c) √54,90,000 (d) none of these Distance between two planes after 1 1/2 hours = AB In right angled Δ AOB By Pythagoras Theorem AB2 = OA2 + OB2 AB2 = (1500)2 + (1800)2 AB2 = 22,50,000 + 32,40,000 AB2 = 54,90,000 + 32,40,000 AB = √𝟓𝟒𝟗𝟎𝟎𝟎𝟎 km So, the correct answer is (c) Question 5 The given problem is based on which concept? (a) Triangles (b) Co-ordinate geometry (c) Height and Distance (d) none of these Since this question involves Pythagoras Theorem Which is in Triangles Class 10 So, the correct answer is (a)