Example 11 - A ladder is placed against a wall such that - Pythagoras Theoram - Finding value

Example 11 - Chapter 6 Class 10 Triangles - Part 2

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Question 3 A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground. Find the length of the ladder. Given :- Distance from wall = BC = 2.5 m Height of window = AC = 6m To Find : Length of ladder i.e. = AB Solution: Since the wall will be perpendicular to ground ∠ ACB = 90° Δ ACB is a right angle triangle So, using Pythagoras theorem (Hypotenuse)2 = (Height)2 + (Base)2 (AB)2 = (AC)2 + (BC)2 AB2 = (6)2 + (2.5)2 AB2 = (6 ×6)+(2.5×2.5) AB2 = 36 + 6.25 AB2 = 42.25 AB = √42.25 AB = 6.5 m Hence, length of the ladder = AB = 6.5 m

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.