Question 3
A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground. Find the length of the ladder.
Given :-
Distance from wall = BC = 2.5 m
Height of window = AC = 6m
To Find : Length of ladder i.e. = AB
Solution:
Since the wall will be perpendicular to ground
∠ ACB = 90°
Δ ACB is a right angle triangle
So, using Pythagoras theorem
(Hypotenuse)2 = (Height)2 + (Base)2
(AB)2 = (AC)2 + (BC)2
AB2 = (6)2 + (2.5)2
AB2 = (6 ×6)+(2.5×2.5)
AB2 = 36 + 6.25
AB2 = 42.25
AB = √42.25
AB = 6.5 m
Hence, length of the ladder = AB = 6.5 m

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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