1. Chapter 6 Class 10 Triangles (Term 1)
  2. Serial order wise
  3. Examples

Example 3 - Chapter 6 Class 10 Triangles (Term 1)

Last updated at May 29, 2018 by

Example 3 - PS/SQ = PT/TR and PST = PRQ. Prove that - Examples

Example 3 - Chapter 6 Class 10 Triangles - Part 2

  1. Chapter 6 Class 10 Triangles (Term 1)
  2. Serial order wise

    3. Examples

    Theorems →

Transcript

Example 3 In figure , / = / and PST = PRQ. Prove that PQR is an isosceles triangle. Given: / = / PST = PRQ To prove: PQR is an isosceles triangles Proof: Given / = / ST II QR Since ST II QR , PST = PQR Also, given PST = PRQ From (1) and (2) PQR = PRQ PR = PQ Therefore , two sides of PQR is equal PQR is an isosceles triangle Hence proved

Chapter 6 Class 10 Triangles (Term 1)
Serial order wise

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.