Ex 6.5

Ex 6.5, 1
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Ex 6.5, 2 Important Deleted for CBSE Board 2023 Exams

Ex 6.5, 3 Important Deleted for CBSE Board 2023 Exams

Ex 6.5, 4 Deleted for CBSE Board 2023 Exams

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Ex 6.5, 6 Deleted for CBSE Board 2023 Exams

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Ex 6.5, 11 Important Deleted for CBSE Board 2023 Exams

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Ex 6.5, 17 (MCQ) Deleted for CBSE Board 2023 Exams

Chapter 6 Class 10 Triangles

Serial order wise

Last updated at May 29, 2018 by Teachoo

Ex 6.5, 12 Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops. Given: Height of first pole = AB = 6 m Height of second pole = CD = 11 m Distance b/w feet of poles = AC = 12 m To Find :- Distance between the tops of the pole ,i.e., BD Solution :- Let we draw a line BE perpendicular to DC i.e. BE DC Since AC is also perpendicular to DC as pole is vertical to ground, So, BE = AC = 12 m Similarly , AB = EC = 6 m Now, DE = DC EC DE = 11 6 DE = 5 m Since BED = 90 as BE DC BED is right triangle Using Pythagoras theorem in right angle triangle AEB (Hypotenuse)2 = (Height)2 + (Base)2 (BD)2 = (DE)2 + (BE)2 (BD)2 = (5)2 + (12)2 (BD)2 = 25 + 144 (BD)2 = 169 BD = 169 BD = (13 13) BD = ((13)2) BD = 13 Hence, the distance between tops of the pole = 13 metre .