Get Real time Doubt solving from 8pm to 12 am!

Ex 6.5

Ex 6.5, 1
Deleted for CBSE Board 2023 Exams

Ex 6.5, 2 Important Deleted for CBSE Board 2023 Exams

Ex 6.5, 3 Important Deleted for CBSE Board 2023 Exams

Ex 6.5, 4 Deleted for CBSE Board 2023 Exams

Ex 6.5, 5 Deleted for CBSE Board 2023 Exams

Ex 6.5, 6 Deleted for CBSE Board 2023 Exams You are here

Ex 6.5, 7 Important Deleted for CBSE Board 2023 Exams

Ex 6.5, 8 Important Deleted for CBSE Board 2023 Exams

Ex 6.5, 9 Deleted for CBSE Board 2023 Exams

Ex 6.5, 10 Deleted for CBSE Board 2023 Exams

Ex 6.5, 11 Important Deleted for CBSE Board 2023 Exams

Ex 6.5, 12 Important Deleted for CBSE Board 2023 Exams

Ex 6.5, 13 Deleted for CBSE Board 2023 Exams

Ex 6.5, 14 Deleted for CBSE Board 2023 Exams

Ex 6.5, 15 Important Deleted for CBSE Board 2023 Exams

Ex 6.5, 16 Deleted for CBSE Board 2023 Exams

Ex 6.5, 17 (MCQ) Deleted for CBSE Board 2023 Exams

Chapter 6 Class 10 Triangles

Serial order wise

Last updated at May 14, 2021 by Teachoo

Ex 6.5,6 ABC is an equilateral triangle of side 2a. Find each of its altitudes. Given: Equilateral triangle ABC with each side 2a Altitude AD is drawn such that AD BC To find: AD Solution: In ADB and ADC AB = AC AD = AD ADB= ADC Hence ADB ADC Hence , BD = DC BD = DC BD = DC = 1/2BC BD = DC = 2 /2 BD = DC = a Hence BD = a Hence in right Using Pythagoras theorem (Hypotenuse)2 = (Height )2 + (Base)2 (AB)2 = (AD)2 + (BD)2 (2a)2 = (AD)2 + a2 4a2 = (AD)2 + a2 4a2 a2 = AD2 3a2 = AD2 AD2 = 3a2 AD = 3 a AD = a 3 Thus, length of altitude AD = a 3 Similarly , length of altitude BE = a 3 length of altitude CF = a 3