Subscribe to our Youtube Channel - https://www.youtube.com/channel/UCZBx269Tl5Os5NHlSbVX4Kg
Ex 6.5, 4 - Chapter 6 Class 10 Triangles
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 6.5, 4 ABC is an isosceles triangle right angled at C. Prove that AB2 = 2AC2 Given: โ ๐ด๐ต๐ถ is right triangle Also โ ๐ด๐ต๐ถ is isosceles To prove: AB2 = 2AC2 Proof: Here, Hypotenuse = AB Also we know that ฮABC is isosceles Hence AC = BC Using Pythagoras theorem in ฮ ACB Hypotenuse2 = (Height)2 + (Base)2 AB2 = AC2 + BC2 AB2 = AC2 + AC2 AB2 = 2 AC2 Hence proved
Chapter 6 Class 10 Triangles
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.