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Ex 6.5, 4 - ABC is an isosceles triangle right angled at C - Ex 6.5

Ex 6.5, 4 - Chapter 6 Class 10 Triangles - Part 2


Transcript

Ex 6.5, 4 ABC is an isosceles triangle right angled at C. Prove that AB2 = 2AC2 Given: ∆ 𝐴𝐵𝐶 is right triangle Also ∆ 𝐴𝐵𝐶 is isosceles To prove: AB2 = 2AC2 Proof: Here, Hypotenuse = AB Also we know that ΔABC is isosceles Hence AC = BC Using Pythagoras theorem in Δ ACB Hypotenuse2 = (Height)2 + (Base)2 AB2 = AC2 + BC2 AB2 = AC2 + AC2 AB2 = 2 AC2 Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.