

Last updated at May 29, 2018 by Teachoo
Ex 6.5, 4 ABC is an isosceles triangle right angled at C. Prove that AB2 = 2AC2 Given: โ ๐ด๐ต๐ถ is right triangle Also โ ๐ด๐ต๐ถ is isosceles To prove: AB2 = 2AC2 Proof: Here, Hypotenuse = AB Also we know that ฮABC is isosceles Hence AC = BC Using Pythagoras theorem in ฮ ACB Hypotenuse2 = (Height)2 + (Base)2 AB2 = AC2 + BC2 AB2 = AC2 + AC2 AB2 = 2 AC2 Hence proved