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Ex 6.5
Ex 6.5, 2 Important Deleted for CBSE Board 2023 Exams
Ex 6.5, 3 Important Deleted for CBSE Board 2023 Exams
Ex 6.5, 4 Deleted for CBSE Board 2023 Exams
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Ex 6.5, 6 Deleted for CBSE Board 2023 Exams
Ex 6.5, 7 Important Deleted for CBSE Board 2023 Exams
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Ex 6.5, 9 Deleted for CBSE Board 2023 Exams
Ex 6.5, 10 Deleted for CBSE Board 2023 Exams
Ex 6.5, 11 Important Deleted for CBSE Board 2023 Exams
Ex 6.5, 12 Important Deleted for CBSE Board 2023 Exams
Ex 6.5, 13 Deleted for CBSE Board 2023 Exams
Ex 6.5, 14 Deleted for CBSE Board 2023 Exams
Ex 6.5, 15 Important Deleted for CBSE Board 2023 Exams
Ex 6.5, 16 Deleted for CBSE Board 2023 Exams
Ex 6.5, 17 (MCQ) Deleted for CBSE Board 2023 Exams
Last updated at March 22, 2023 by Teachoo
Ex 6.5, 5 ABC is an isosceles triangle with AC = BC. If AB2 = 2AC2, prove that ABC is a right triangle. Given: ABC is an isosceles triangle. where, AC = BC & AB2 = 2 AC2 To prove: ABC is a right angle triangle . Proof: Given AB2 = 2AC2 AB2 = AC2 + AC2 AB2 = AC2 + BC2 So, AB will be the largest side, i.e. Hypotenuse = AB Now, we prove Pythagoras theorem , (Hypotenuse)2 = (Height )2 + (Base)2 L.H.S (Hypotenuse)2 = AB2 R.H.S (Height )2 + (Base)2 = (AC)2 + (BC)2 = (AC)2 + (AC)2 (Given AC = BC) = 2(AC)2 = AB2 (Given AB2 = 2AC2) Since L.H.S = R.H.S , Pythagoras theorem is satisfied Hence ABC is a right angled triangle