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Ex 6.5, 9 - A ladder 10 m long reaches a window 8 m - Pythagoras Theoram - Finding value

Ex 6.5, 9 - Chapter 6 Class 10 Triangles - Part 2

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Ex 6.5, 9 A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall. Given :- Height of window = AC = 8m Length of ladder = AB = 10 m To Find : Distance of foot of ladder from wall i.e. BC Solution: Since the wall will be perpendicular to ground ACB = 90 ACB is a right angle triangle So, using Pythagoras theorem (Hypotenuse)2 = (Height)2 + (Base)2 (AB)2 = (AC)2 + (BC)2 (10)2 = (8)2 + (BC)2 100 = 64 + (BC)2 100 64 = (BC)2 36 = (BC)2 (BC)2 = 36 BC = 36 BC = (6 6) BC = ((6)2) BC = 6 m Hence, distance of the foot of the ladder from base of the wall (BC) = 6 m.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.