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Ex 6.3

Ex 6.3, 1 (i)

Ex 6.3, 1 (ii)

Ex 6.3, 1 (iii)

Ex 6.3, 1 (iv)

Ex 6.3, 1 (v) Important

Ex 6.3, 1 (vi)

Ex 6.3, 2

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Ex 6.3, 4 Important

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Ex 6.3, 11 Important

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Ex 6.3, 15 Important You are here

Ex 6.3, 16

Chapter 6 Class 10 Triangles

Serial order wise

Last updated at June 23, 2017 by Teachoo

Ex 6.3, 15 A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower. Given: Height of pole = AB = 6m Length of pole of shadow = BC = 4 m Length of shadow of tower = EF = 28 To Find : Height of tower i.e ED Solution:- In β π΄π΅πΆ and β π·πΈπΉ β B = β E = 90Β° β πΆ=β πΉ β΄ β π΄π΅πΆ βΌ β π·πΈπΉ β π΄π΅πΆ βΌ β π·πΈπΉ We know that if two triangles are similar, ratio of their sides are in proportion So, π΄π΅/π·πΈ=π΅πΆ/πΈπΉ 6/π·πΈ=4/28 6 Γ28=π·πΈΓ4 (6 Γ 28)/4= π·πΈ 6 Γ7=π·πΈ π·πΈ = 42 Hence, the height of the tower is 42 metres