Ex 6.3

Ex 6.3, 1 (i)

Ex 6.3, 1 (ii)

Ex 6.3, 1 (iii)

Ex 6.3, 1 (iv)

Ex 6.3, 1 (v) Important

Ex 6.3, 1 (vi)

Ex 6.3, 2

Ex 6.3, 3

Ex 6.3, 4 Important

Ex 6.3, 5

Ex 6.3, 6

Ex 6.3, 7

Ex 6.3, 8 Important

Ex 6.3, 9

Ex 6.3, 10

Ex 6.3, 11 Important

Ex 6.3, 12 Important

Ex 6.3, 13 Important

Ex 6.3, 14 Important

Ex 6.3, 15 Important You are here

Ex 6.3, 16

Last updated at April 16, 2024 by Teachoo

Ex 6.3, 15 A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower. Given: Height of pole = AB = 6m Length of pole of shadow = BC = 4 m Length of shadow of tower = EF = 28 To Find : Height of tower i.e ED Solution:- In β π΄π΅πΆ and β π·πΈπΉ β B = β E = 90Β° β πΆ=β πΉ β΄ β π΄π΅πΆ βΌ β π·πΈπΉ β π΄π΅πΆ βΌ β π·πΈπΉ We know that if two triangles are similar, ratio of their sides are in proportion So, π΄π΅/π·πΈ=π΅πΆ/πΈπΉ 6/π·πΈ=4/28 6 Γ28=π·πΈΓ4 (6 Γ 28)/4= π·πΈ 6 Γ7=π·πΈ π·πΈ = 42 Hence, the height of the tower is 42 metres