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Ex 6.3, 9 - Chapter 6 Class 10 Triangles (Term 1)
Last updated at May 29, 2018 by Teachoo
Ex 6.3
Ex 6.3, 1 (i)
Ex 6.3, 1 (ii)
Ex 6.3, 1 (iii)
Ex 6.3, 1 (iv)
Ex 6.3, 1 (v) Important
Ex 6.3, 1 (vi)
Ex 6.3, 2
Ex 6.3, 3
Ex 6.3, 4 Important
Ex 6.3, 5
Ex 6.3, 6
Ex 6.3, 7
Ex 6.3, 8 Important
Ex 6.3, 9 You are here
Ex 6.3, 10
Ex 6.3, 11 Important
Ex 6.3, 12 Important
Ex 6.3, 13 Important
Ex 6.3, 14 Important
Ex 6.3, 15 Important
Ex 6.3, 16
Chapter 6 Class 10 Triangles
Serial order wise
Transcript
Ex 6.3, 9 In figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: ΔABC ∼ ΔAMP Given:- ABC and AMP are two right triangles, ∠ ABC = 90° , ∠ AMP = 90° To Prove :- ΔABC ∼ ΔAMP Proof: In ΔABC and ΔAMP ∠CAB = ∠MAP ∠ABC = ∠AMP Using AA similarity So, ΔABC ∼ ΔAMP Ex 6.3, 9 In figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (ii) 𝐶𝐴/𝑃𝐴 = 𝐵𝐶/𝑀𝑃 In the first part we proved, ΔABC ∼ ΔAMP And we know that if two triangles are similar , the ratio of their corresponding sides is proportional 𝐶𝐴/𝑃𝐴 = 𝐵𝐶/𝑀𝑃 = 𝐴𝐵/𝐴𝑀 𝐶𝐴/𝑃𝐴 = 𝐵𝐶/𝑀𝑃 Hence proved
