Ex 6.3, 9 - Chapter 6 Class 10 Triangles

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Ex 6.3, 9 - ABC and AMP are two right triangles. Prove - AA Similarity

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Ex 6.3, 9 - Chapter 6 Class 10 Triangles - Part 2

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Ex 6.3, 9 In figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: ΔABC ∼ ΔAMP Given:- ABC and AMP are two right triangles, ∠ ABC = 90° , ∠ AMP = 90° To Prove :- ΔABC ∼ ΔAMP Proof: In ΔABC and ΔAMP ∠CAB = ∠MAP ∠ABC = ∠AMP Using AA similarity So, ΔABC ∼ ΔAMP Ex 6.3, 9 In figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (ii) 𝐶𝐴/𝑃𝐴 = 𝐵𝐶/𝑀𝑃 In the first part we proved, ΔABC ∼ ΔAMP And we know that if two triangles are similar , the ratio of their corresponding sides is proportional 𝐶𝐴/𝑃𝐴 = 𝐵𝐶/𝑀𝑃 = 𝐴𝐵/𝐴𝑀 𝐶𝐴/𝑃𝐴 = 𝐵𝐶/𝑀𝑃 Hence proved

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