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Ex 6.3, 9 - ABC and AMP are two right triangles. Prove - AA Similarity

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Ex 6.3, 9 - Chapter 6 Class 10 Triangles - Part 2

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Ex 6.3, 9 In figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: ΔABC ∼ ΔAMP Given:- ABC and AMP are two right triangles, ∠ ABC = 90° , ∠ AMP = 90° To Prove :- ΔABC ∼ ΔAMP Proof: In ΔABC and ΔAMP ∠CAB = ∠MAP ∠ABC = ∠AMP Using AA similarity So, ΔABC ∼ ΔAMP Ex 6.3, 9 In figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (ii) 𝐶𝐴/𝑃𝐴 = 𝐵𝐶/𝑀𝑃 In the first part we proved, ΔABC ∼ ΔAMP And we know that if two triangles are similar , the ratio of their corresponding sides is proportional 𝐶𝐴/𝑃𝐴 = 𝐵𝐶/𝑀𝑃 = 𝐴𝐵/𝐴𝑀 𝐶𝐴/𝑃𝐴 = 𝐵𝐶/𝑀𝑃 Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.